What is the limit as x approaches 6 of (x^2-3x-18)/(x-6) ?

The limit as x approaches 6 of (x^2-3x-18)/(x-6) is 9

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limit as x approaches 6 of (x^2-3x-18)/(x-6)

x \to 6 lim (\frac{x ^{2} - 3 x - 18}{x - 6})

9

Solution steps

x \to 6 lim (\frac{x ^{2} - 3 x - 18}{x - 6})

Simplify

\frac{x ^{2} - 3 x - 18}{x - 6} : x + 3

= x \to 6 lim (x + 3)

Plug in the value

x = 6

= 6 + 3

Simplify

= 9

What is the limit as x approaches 6 of (x^2-3x-18)/(x-6) ?
The limit as x approaches 6 of (x^2-3x-18)/(x-6) is 9