(xy-1)dx+(x^2-xy)dy=0

解答

(x y - 1) d x + (x^{2} - x y) d y = 0

y = x - x^{2} - 2 ln (x) - c_{1}, y = x + x^{2} - 2 ln (x) - c_{1}

求解步骤

(x y - 1) d x + (x^{2} - x y) d y = 0

求解恰当方程:

y = x - x^{2} - 2 ln (x) - c_{1}, y = x + x^{2} - 2 ln (x) - c_{1}

y = x - x^{2} - 2 ln (x) - c_{1}, y = x + x^{2} - 2 ln (x) - c_{1}

\frac{d y}{d x} = y (10 - y)

\frac{d}{d x} (8 sin (x) - 8 x cos (x))

d er i v a t i v e ln (9 x)

d er i v a t i v e f (x) = 2 x^{3} - 3 x^{2} - 72 x + 108

\int (csc^{2} (t) - 2 e^{t}) d t