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Beliebt Rechnen >

integral from 0 to 1 of x^4(2+2x^5)

Lösung

\int_{0}^{1} x^{4} (2 + 2 x^{5}) d x

Lösung

\frac{3}{5}

+1

Dezimale

0.6

Schritte zur Lösung

\int_{0}^{1} x^{4} (2 + 2 x^{5}) d x

Wende die partielle Integration an

= [\frac{1}{5} x^{5} (2 + 2 x^{5}) - \int 2 x^{9} d x]_{0}^{1}

\int 2 x^{9} d x = \frac{x ^{10}}{5}

= [\frac{1}{5} x^{5} (2 + 2 x^{5}) - \frac{x ^{10}}{5}]_{0}^{1}

Vereinfache

[\frac{1}{5} x^{5} (2 + 2 x^{5}) - \frac{x ^{10}}{5}]_{0}^{1} : [\frac{1}{5} (2 x^{5} + x^{10})]_{0}^{1}

= [\frac{1}{5} (2 x^{5} + x^{10})]_{0}^{1}

Berechne die Grenzen:

\frac{3}{5}

= \frac{3}{5}

Graph

Beliebte Beispiele

(d^2)/(dx^2)(xsqrt(1-x^2))

\frac{d ^{2}}{d x ^{2}} (x 1 - x^{2})

integral from 0 to r of xsqrt(r^2-x^2)

\int_{0}^{r} x r^{2} - x^{2} d x

integral of x/((x^2-4)(x+3))

\int \frac{x}{( x ^{2} - 4 ) ( x + 3 )} d x

integral of 15^x

\int 1 5^{x} d x

tangent f(x)= 5/(2sqrt(5x+6)),\at x=2

t an g e n t f (x) = \frac{5}{2 5 x + 6}, at x = 2