limit as t approaches 1+of (|1-t|)/(1-t)

Lösung

t \to 1 + lim (\frac{∣ 1 - t ∣}{1 - t})

- 1

Schritte zur Lösung

t \to 1 + lim (\frac{∣ 1 - t ∣}{1 - t})

1 - t

ist negativ wenn

t \to 1 +

. Deshalb

∣ 1 - t ∣ = - 1 + t

= t \to 1 + lim (\frac{- 1 + t}{1 - t})

\frac{- 1 + t}{1 - t} = - 1

= t \to 1 + lim (- 1)

x \to a lim c = c

= - 1

\frac{d}{d x} (e^{x^{2} - y^{2}})

x \to \frac{π}{2} lim (6 sec (x))

h \to 0 lim (m x + b)

x \to 0 lim (\frac{5}{2 x})

\frac{\partial}{\partial y} (- x sin (x y))