derivative of x^4+8

解答

\frac{d}{d x} (x^{4} + 8)

4 x^{3}

求解步骤

\frac{d}{d x} (x^{4} + 8)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (8)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (8) = 0

= 4 x^{3} + 0

化简

= 4 x^{3}

x \to - \infty lim (5 + x^{2})

\frac{d y}{d x} = x y

f (x) = arctan (x)

\int \frac{1}{16 + y ^{2}} d y

a re a y = x^{2} - 30, y = 10 - 3 x