integral from 1 to 3 of 2x+1

Lösung

\int_{1}^{3} 2 x + 1 d x

10

Schritte zur Lösung

\int_{1}^{3} 2 x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 2 x d x + \int_{1}^{3} 1 d x

\int_{1}^{3} 2 x d x = 8

\int_{1}^{3} 1 d x = 2

= 8 + 2

Vereinfache

= 10

x \to 2 lim (x - 1)

d er i v a t i v e π x

\int \frac{7 x ^{2} + 4 x + 7}{x ^{3} - 1} d x

\int_{- 3}^{3} (\frac{18}{9 + x ^{2}} - 1) d x

2 \frac{d y}{d x} + 4 y = - 8 y^{3}