derivative of 4sqrt(7x^2+9)

Lösung

\frac{d}{d x} (4 7 x^{2} + 9)

\frac{28 x}{7 x ^{2} + 9}

Schritte zur Lösung

\frac{d}{d x} (4 7 x^{2} + 9)

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (7 x^{2} + 9)

Wende die Kettenregel an:

\frac{1}{2 7 x ^{2} + 9} \frac{d}{d x} (7 x^{2} + 9)

= \frac{1}{2 7 x ^{2} + 9} \frac{d}{d x} (7 x^{2} + 9)

\frac{d}{d x} (7 x^{2} + 9) = 14 x

= 4 \cdot \frac{1}{2 7 x ^{2} + 9} \cdot 14 x

Vereinfache

4 \cdot \frac{1}{2 7 x ^{2} + 9} \cdot 14 x : \frac{28 x}{7 x ^{2} + 9}

= \frac{28 x}{7 x ^{2} + 9}

\frac{\partial}{\partial x} (4 ln (\frac{2 x y}{7 z}))

d er i v a t i v e h (w) = \frac{4 w ^{5} - w}{w}

\int x e^{1 - x} d x

f (x) = x sin (\frac{1}{x})

t an g e n t y = x^{2} - 3 x - 2, (2, - 4)