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Popular Calculus >

integral from 1 to 2 of (2x^2-2)

Solution

\int_{1}^{2} (2 x^{2} - 2) d x

Solution

\frac{8}{3}

+1

Decimal

2.66666 \dots

Solution steps

\int_{1}^{2} 2 x^{2} - 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 2 x^{2} d x - \int_{1}^{2} 2 d x

\int_{1}^{2} 2 x^{2} d x = \frac{14}{3}

\int_{1}^{2} 2 d x = 2

= \frac{14}{3} - 2

Simplify

\frac{14}{3} - 2 : \frac{8}{3}

= \frac{8}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (2x^2-2) ?
The integral from 1 to 2 of (2x^2-2) is 8/3