What is the tangent of f(x)=xsqrt(x),\at x=16 ?

The tangent of f(x)=xsqrt(x),\at x=16 is y=6x-32

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tangent of f(x)=xsqrt(x),\at x=16

tangent of

f (x) = x x, at x = 16

y = 6 x - 32

Solution steps

Find the tangent point:

(16, 64)

Find the slope of

f (x) = x x : \frac{df ( x )}{d x} = \frac{3 x}{2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 6

Find the line with slope m=

6

and passing through

(16, 64) : y = 6 x - 32

y = 6 x - 32

What is the tangent of f(x)=xsqrt(x),\at x=16 ?
The tangent of f(x)=xsqrt(x),\at x=16 is y=6x-32