y^'=1-sin(y),y(0)=0

Lösung

y^{^{'}} = 1 - sin (y), y (0) = 0

y = 2 arctan (\frac{t}{t + 2}) + 2 πn

Schritte zur Lösung

y^{'} (t) = 1 - sin (y)

Solve separable ODE:

y = 2 arctan (\frac{t}{t + 2}) + 2 πn

y = 2 arctan (\frac{t}{t + 2}) + 2 πn

\int_{- 1}^{1} 3 x^{2} (2 x^{3} + 1)^{2} d x

x \to 0 + lim (\frac{x ^{2} - 3 x + 2}{x ^{3} - 2 x ^{2}})

x^{2} (\frac{d y}{d x}) + x y = 1

x \to 0 lim (\frac{e ^{x^{2}} - 1}{x})

d er i v a t i v e \frac{x}{x ^{3} + 1}