x^{''}-0x^'+x=0

Lösung

x^{^{''}} - 0 x^{^{'}} + x = 0

x = c_{1} cos (t) + c_{2} sin (t)

Schritte zur Lösung

x^{''} (t) - 0 x^{'} (t) + x = 0

Solve linear ODE:

x = c_{1} cos (t) + c_{2} sin (t)

x = c_{1} cos (t) + c_{2} sin (t)

\int 6 d x

\frac{\partial}{\partial y} (\frac{- y}{x ^{2} + y ^{2}})

\int_{- \infty}^{0} e^{- x} d x

x \to 1 lim (x^{2} + 3 x - 1)

t \to π lim (tan (\frac{5 t}{4}))