derivative of sqrt(-2x^2+1)

解答

\frac{d}{d x} (- 2 x^{2} + 1)

- \frac{2 x}{- 2 x ^{2} + 1}

求解步骤

\frac{d}{d x} (- 2 x^{2} + 1)

使用连锁律:

\frac{1}{2 - 2 x ^{2} + 1} \frac{d}{d x} (- 2 x^{2} + 1)

= \frac{1}{2 - 2 x ^{2} + 1} \frac{d}{d x} (- 2 x^{2} + 1)

\frac{d}{d x} (- 2 x^{2} + 1) = - 4 x

= \frac{1}{2 - 2 x ^{2} + 1} (- 4 x)

化简

\frac{1}{2 - 2 x ^{2} + 1} (- 4 x) : - \frac{2 x}{- 2 x ^{2} + 1}

= - \frac{2 x}{- 2 x ^{2} + 1}

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