integral from 0 to 4 of (2x^2+8)

解

\int_{0}^{4} (2 x^{2} + 8) d x

\frac{224}{3}

十進法表記

74.66666 \dots

解答ステップ

\int_{0}^{4} 2 x^{2} + 8 d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 2 x^{2} d x + \int_{0}^{4} 8 d x

\int_{0}^{4} 2 x^{2} d x = \frac{128}{3}

\int_{0}^{4} 8 d x = 32

= \frac{128}{3} + 32

簡素化

\frac{128}{3} + 32 : \frac{224}{3}

= \frac{224}{3}