d/(dt)(1-2cos(t))

Lösung

\frac{d}{d t} (1 - 2 cos (t))

2 sin (t)

Schritte zur Lösung

\frac{d}{d t} (1 - 2 cos (t))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (1) - \frac{d}{d t} (2 cos (t))

\frac{d}{d t} (1) = 0

\frac{d}{d t} (2 cos (t)) = - 2 sin (t)

= 0 - (- 2 sin (t))

Vereinfache

= 2 sin (t)

\int \frac{8 x + 9}{( x ^{2} + 9 ) ( 8 - x )} d x

\int \frac{1}{6 y} d y

\int \frac{1}{49 + t ^{2}} d t

t an g e n t y = sin (x), at x = \frac{7 π}{6}

x \to 0.9 lim (2 x^{2} - 5 x + 1)