y^'=(x^2y-y)/(y+1)

解答

y^{^{'}} = \frac{x ^{2} y - y}{y + 1}

y = W (\frac{1}{e ^{\frac{- x ^{3} + 3 x - c _{1}}{3}}})

求解步骤

y^{'} (x) = \frac{x ^{2} y - y}{y + 1}

求解可分离方程:

y = W (\frac{1}{e ^{\frac{- x ^{3} + 3 x - c _{1}}{3}}})

y = W (\frac{1}{e ^{\frac{- x ^{3} + 3 x - c _{1}}{3}}})

\int 2 x - 5 d x

x \to 2 lim ((3 - x)^{2})

\int (3 x^{2} - 7 x)^{5} (6 x - 7) d x

\int x (e^{(3 x - 2)} + 5) d x

ma c l a u r in tan (θ)