(dy)/(dx)=(y^2+3xsqrt(x^2+y^2))/(xy)

Lösung

\frac{d y}{d x} = \frac{y ^{2} + 3 x x ^{2} + y ^{2}}{x y}

y = 9 ln^{2} (x) + 6 c_{1} ln (x) + c_{1}^{2} - 1 x, y = - x 9 ln^{2} (x) + 6 c_{1} ln (x) + c_{1}^{2} - 1

Schritte zur Lösung

\frac{d y}{d x} = \frac{y ^{2} + 3 x x ^{2} + y ^{2}}{x y}

Solve using substitution:

y = 9 ln^{2} (x) + 6 c_{1} ln (x) + c_{1}^{2} - 1 x, y = - x 9 ln^{2} (x) + 6 c_{1} ln (x) + c_{1}^{2} - 1

y = 9 ln^{2} (x) + 6 c_{1} ln (x) + c_{1}^{2} - 1 x, y = - x 9 ln^{2} (x) + 6 c_{1} ln (x) + c_{1}^{2} - 1

x \to 0 + lim (- csc^{2} (x))

\frac{d}{d x} (x^{2} (x + 3)^{10})

a re a y = x^{3} - 2 x^{2} + 2, y = 3 x^{2} + 3 x - 13

\frac{d}{d x} f^{- 1} (x) = 2 x + ln (x + 1)

\int (1 - x)^{- 2} d x