(\partial)/(\partial y)(16-4x^2-y^2)

Lösung

\frac{\partial}{\partial y} (16 - 4 x^{2} - y^{2})

- 2 y

Schritte zur Lösung

\frac{\partial}{\partial y} (16 - 4 x^{2} - y^{2})

Behandle

x

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (16) - \frac{\partial}{\partial y} (4 x^{2}) - \frac{\partial}{\partial y} (y^{2})

\frac{\partial}{\partial y} (16) = 0

\frac{\partial}{\partial y} (4 x^{2}) = 0

\frac{\partial}{\partial y} (y^{2}) = 2 y

= 0 - 0 - 2 y

Vereinfache

= - 2 y

d er i v a t i v e g (x) = x^{2} (1 - 5 x)

\frac{\partial}{\partial x} (2 z^{3} - 3 (x^{2} + y^{2}) z)

x \to - 8 + lim (\frac{x}{x + 8})

\frac{\partial}{\partial x} (6 x^{3} y + 6 y^{5} + 1)

\int_{1}^{R} x^{- \frac{7}{5}} d x