derivative 0.49489nv^2+1500*n/v

Lösung

ableitung von

0.49489 n v^{2} + 1500 \cdot \frac{n}{v}

0.98978 n v - \frac{1500 n}{v ^{2}}

Schritte zur Lösung

\frac{d}{d v} (0.49489 n v^{2} + 1500 \cdot \frac{n}{v})

Vereinfache

0.49489 n v^{2} + 1500 \cdot \frac{n}{v} : 0.49489 n v^{2} + \frac{1500 n}{v}

= \frac{d}{d v} (0.49489 n v^{2} + \frac{1500 n}{v})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d v} (0.49489 n v^{2}) + \frac{d}{d v} (\frac{1500 n}{v})

\frac{d}{d v} (0.49489 n v^{2}) = 0.98978 n v

\frac{d}{d v} (\frac{1500 n}{v}) = - \frac{1500 n}{v ^{2}}

= 0.98978 n v - \frac{1500 n}{v ^{2}}

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