limit as x approaches-infinity of 1/9 arctan(x)

解答

x \to - \infty lim (\frac{1}{9} arctan (x))

- \frac{π}{18}

十进制

- 0.17453 \dots

求解步骤

x \to - \infty lim (\frac{1}{9} arctan (x))

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= \frac{1}{9} \cdot x \to - \infty lim (arctan (x))

运用一般极限法则:

x \to - \infty lim (arctan (x)) = - \frac{π}{2}

= \frac{1}{9} (- \frac{π}{2})

化简

\frac{1}{9} (- \frac{π}{2}) : - \frac{π}{18}

= - \frac{π}{18}

\frac{d}{d x} (ln (3 x))

\int_{- 1}^{0} \frac{6}{1 + ( 2 x + 1 ) ^{2}} d x

\frac{\partial}{\partial y} (y e^{x y} + sin (y))

\int e^{a x} sin (b x) d x

\frac{\partial}{\partial x} (e^{- x} sin (y) z)