integral from 1/2 to 1 of x^{-3}-8

Lösung

\int_{\frac{1}{2}}^{1} x^{- 3} - 8 d x

- \frac{5}{2}

Dezimale

- 2.5

Schritte zur Lösung

\int_{\frac{1}{2}}^{1} x^{- 3} - 8 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{\frac{1}{2}}^{1} x^{- 3} d x - \int_{\frac{1}{2}}^{1} 8 d x

\int_{\frac{1}{2}}^{1} x^{- 3} d x = \frac{3}{2}

\int_{\frac{1}{2}}^{1} 8 d x = 4

= \frac{3}{2} - 4

Vereinfache

\frac{3}{2} - 4 : - \frac{5}{2}

= - \frac{5}{2}

n = 1 \sum \infty x^{n} 8^{n}

\int \frac{3 x - 2}{x} d x

in v erse l a pl a ce \frac{1}{( s ) ( s + 2 ) ( s + 3 )}

y^{^{'}} = \frac{e ^{x - y}}{1 + e ^{x}}, y (1) = 0

\frac{d}{d x} (9 3 + tan (x))