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Beliebt Rechnen >

y^{''}+12y^'+36=0,y(1)=0,y^'(1)=1

Lösung

y^{^{''}} + 12 y^{^{'}} + 36 = 0, y (1) = 0, y^{^{'}} (1) = 1

Lösung

y = \frac{1}{3} + 3 - \frac{e ^{12}}{3} e^{- 12 t} - 3 t

Schritte zur Lösung

y^{''} (t) + 12 y^{'} (t) + 36 = 0

Solve linear ODE:

y = \frac{1}{3} + 3 - \frac{e ^{12}}{3} e^{- 12 t} - 3 t

y = \frac{1}{3} + 3 - \frac{e ^{12}}{3} e^{- 12 t} - 3 t

Graph

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