integral of sec(38x)tan(38x)

解答

\int sec (38 x) tan (38 x) d x

\frac{1}{38} sec (38 x) + C

求解步骤

\int sec (38 x) tan (38 x) d x

使用换元积分法

= \int \frac{1}{38} d u

常数积分:

\int a d x = a x

= \frac{1}{38} u

u = sec (38 x)

代回

= \frac{1}{38} sec (38 x)

解答补常数

= \frac{1}{38} sec (38 x) + C

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