derivative of sqrt(x^3-8)

解答

\frac{d}{d x} (x^{3} - 8)

\frac{3 x ^{2}}{2 x ^{3} - 8}

求解步骤

\frac{d}{d x} (x^{3} - 8)

使用连锁律:

\frac{1}{2 x ^{3} - 8} \frac{d}{d x} (x^{3} - 8)

= \frac{1}{2 x ^{3} - 8} \frac{d}{d x} (x^{3} - 8)

\frac{d}{d x} (x^{3} - 8) = 3 x^{2}

= \frac{1}{2 x ^{3} - 8} \cdot 3 x^{2}

化简

\frac{1}{2 x ^{3} - 8} \cdot 3 x^{2} : \frac{3 x ^{2}}{2 x ^{3} - 8}

= \frac{3 x ^{2}}{2 x ^{3} - 8}

y^{^{'}} + 2 y = 25 sin (x) + 40 cos (x), y (0) = 1

t an g e n t y = x, (9, 3)

n = 6 \sum \infty \frac{5 ^{n}}{1 2 ^{n}}

3 y^{^{''}} + 17 y^{^{'}} - 6 y = 0

\frac{d}{d x} (\frac{1}{x ^{4}} + \frac{1}{x ^{2}} - x^{3})