What is the tangent of y=(2x)/(x-1),(-1,1) ?

The tangent of y=(2x)/(x-1),(-1,1) is y=-1/2 x+1/2

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tangent of y=(2x)/(x-1),(-1,1)

tangent of

y = \frac{2 x}{x - 1}, (- 1, 1)

y = - \frac{1}{2} x + \frac{1}{2}

Solution steps

Find the slope of

y = \frac{2 x}{x - 1} : \frac{d y}{d x} = - \frac{2}{( x - 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(- 1, 1) : y = - \frac{1}{2} x + \frac{1}{2}

y = - \frac{1}{2} x + \frac{1}{2}

What is the tangent of y=(2x)/(x-1),(-1,1) ?
The tangent of y=(2x)/(x-1),(-1,1) is y=-1/2 x+1/2