derivative e^{1+(ln(x))^2}

Lösung

ableitung von

e^{1 + (l n (x))^{2}}

\frac{2 e ^{1 + l n^{2} (x)} ln ( x )}{x}

Schritte zur Lösung

\frac{d}{d x} (e^{1 + (l n (x))^{2}})

Wende die Kettenregel an:

e^{1 + (l n (x))^{2}} \frac{d}{d x} (1 + (ln (x))^{2})

= e^{1 + (l n (x))^{2}} \frac{d}{d x} (1 + (ln (x))^{2})

\frac{d}{d x} (1 + (ln (x))^{2}) = \frac{2 ln ( x )}{x}

= e^{1 + (l n (x))^{2}} \frac{2 ln ( x )}{x}

Multipliziere Brüche:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 e ^{1 + l n^{2} (x)} ln ( x )}{x}

1 - y^{2} d x - 1 - x^{2} d y = 0, y (0) = \frac{1}{2}

y^{^{'}} = e^{t - y}

\int (3 x - 11) e^{x} d x

3 y^{^{''}} - 7 y^{^{'}} + 2 y = 0, y (0) = - 3, y^{^{'}} (0) = - 8

\int sin (x) - 8 cos (x) d x