What is the tangent of f(x)= 9/x ?

The tangent of f(x)= 9/x is y=-9/(a_{0)^2}x+(18)/(a_{0)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)= 9/x

tangent of

f (x) = \frac{9}{x}

y = - \frac{9}{a _{0}^{2}} x + \frac{18}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{9}{a _{0}})

Find the slope of

f (x) = \frac{9}{x} : \frac{df ( x )}{d x} = - \frac{9}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{9}{a _{0}^{2}}

Find the line with slope m=

- \frac{9}{a _{0}^{2}}

and passing through

(a_{0}, \frac{9}{a _{0}}) : y = - \frac{9}{a _{0}^{2}} x + \frac{18}{a _{0}}

y = - \frac{9}{a _{0}^{2}} x + \frac{18}{a _{0}}

What is the tangent of f(x)= 9/x ?
The tangent of f(x)= 9/x is y=-9/(a_{0)^2}x+(18)/(a_{0)}