What is the d/(dy)(-x^2y^2sin(x)+2xy^2cos(x)) ?

The d/(dy)(-x^2y^2sin(x)+2xy^2cos(x)) is -2x^2ysin(x)+4xycos(x)

What is the first d/(dy)(-x^2y^2sin(x)+2xy^2cos(x)) ?

The first d/(dy)(-x^2y^2sin(x)+2xy^2cos(x)) is -2x^2ysin(x)+4xycos(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d y} (- x^{2} y^{2} sin (x) + 2 x y^{2} cos (x))

- 2 x^{2} y sin (x) + 4 x y cos (x)

Solution steps

\frac{d}{d y} (- x^{2} y^{2} sin (x) + 2 x y^{2} cos (x))

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d y} (x^{2} y^{2} sin (x)) + \frac{d}{d y} (2 x y^{2} cos (x))

\frac{d}{d y} (x^{2} y^{2} sin (x)) = 2 x^{2} y sin (x)

\frac{d}{d y} (2 x y^{2} cos (x)) = 4 x y cos (x)

= - 2 x^{2} y sin (x) + 4 x y cos (x)

What is the d/(dy)(-x^2y^2sin(x)+2xy^2cos(x)) ?
The d/(dy)(-x^2y^2sin(x)+2xy^2cos(x)) is -2x^2ysin(x)+4xycos(x)
What is the first d/(dy)(-x^2y^2sin(x)+2xy^2cos(x)) ?
The first d/(dy)(-x^2y^2sin(x)+2xy^2cos(x)) is -2x^2ysin(x)+4xycos(x)