What is the tangent of f(x)=3x^3-x^2+7,\at x=2 ?

The tangent of f(x)=3x^3-x^2+7,\at x=2 is y=32x-37

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tangent of f(x)=3x^3-x^2+7,\at x=2

tangent of

f (x) = 3 x^{3} - x^{2} + 7, at x = 2

y = 32 x - 37

Solution steps

Find the tangent point:

(2, 27)

Find the slope of

f (x) = 3 x^{3} - x^{2} + 7 : \frac{df ( x )}{d x} = 9 x^{2} - 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 32

Find the line with slope m=

32

and passing through

(2, 27) : y = 32 x - 37

y = 32 x - 37

What is the tangent of f(x)=3x^3-x^2+7,\at x=2 ?
The tangent of f(x)=3x^3-x^2+7,\at x=2 is y=32x-37