y^'=-y/x+e^x

Lösung

y^{^{'}} = - \frac{y}{x} + e^{x}

y = e^{x} - \frac{e ^{x}}{x} + \frac{c _{1}}{x}

Schritte zur Lösung

y^{'} (x) = - \frac{y}{x} + e^{x}

Solve linear ODE:

y = e^{x} - \frac{e ^{x}}{x} + \frac{c _{1}}{x}

y = e^{x} - \frac{e ^{x}}{x} + \frac{c _{1}}{x}

d er i v a t i v e f (x) = sin (3 x) - cos (2 x)

\frac{\partial}{\partial x} (x^{3} + 4)

\int_{0}^{1} e^{- s t} t d t

y^{^{'}} = - 2 x tan (y)

s l o p e (5, - 2), (7, 10)