y^'+y=2e^{-t}

Lösung

y^{^{'}} + y = 2 e^{- t}

y = \frac{2 t}{e ^{t}} + \frac{c _{1}}{e ^{t}}

Schritte zur Lösung

y^{'} (t) + y = 2 e^{- t}

Solve linear ODE:

y = \frac{2 t}{e ^{t}} + \frac{c _{1}}{e ^{t}}

y = \frac{2 t}{e ^{t}} + \frac{c _{1}}{e ^{t}}

\int_{0}^{2} t e^{- 1} d t

d er i v a t i v e f (x) = 5 x + x^{2}

\frac{\partial}{\partial x} (4 y sin (x^{2} y))

\int_{0}^{\frac{π}{2}} sin^{3} (t) d t

\frac{d}{d x} (\frac{3 x ^{2} - 2}{2 x + 3})