(1/x)dy=sin(x)(y^3+y)dx

Lösung

(\frac{1}{x}) d y = sin (x) (y^{3} + y) d x

y = \frac{1}{e ^{2 x c o s (x) - 2 s i n (x) - c_{1}} - 1}, y = - \frac{1}{e ^{2 x c o s (x) - 2 s i n (x) - c_{1}} - 1}

Schritte zur Lösung

(\frac{1}{x}) d y = sin (x) (y^{3} + y) d x

Solve Bernoulli ODE:

y = \frac{1}{e ^{2 x c o s (x) - 2 s i n (x) - c_{1}} - 1}, y = - \frac{1}{e ^{2 x c o s (x) - 2 s i n (x) - c_{1}} - 1}

y = \frac{1}{e ^{2 x c o s (x) - 2 s i n (x) - c_{1}} - 1}, y = - \frac{1}{e ^{2 x c o s (x) - 2 s i n (x) - c_{1}} - 1}