What is the derivative of-1/((3+t)^2) ?

The derivative of-1/((3+t)^2) is 2/((3+t)^3)

What is the first derivative of-1/((3+t)^2) ?

The first derivative of-1/((3+t)^2) is 2/((3+t)^3)

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derivative of

- \frac{1}{( 3 + t ) ^{2}}

\frac{2}{( 3 + t ) ^{3}}

Solution steps

\frac{d}{d t} (- \frac{1}{( 3 + t ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d t} (\frac{1}{( 3 + t ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - \frac{d}{d t} ((3 + t)^{- 2})

Apply the chain rule:

- \frac{2}{( 3 + t ) ^{3}} \frac{d}{d t} (3 + t)

= - \frac{2}{( 3 + t ) ^{3}} \frac{d}{d t} (3 + t)

\frac{d}{d t} (3 + t) = 1

= - (- \frac{2}{( 3 + t ) ^{3}} \cdot 1)

Simplify

= \frac{2}{( 3 + t ) ^{3}}

What is the derivative of-1/((3+t)^2) ?
The derivative of-1/((3+t)^2) is 2/((3+t)^3)
What is the first derivative of-1/((3+t)^2) ?
The first derivative of-1/((3+t)^2) is 2/((3+t)^3)