laplacetransform-4sin(4t)

Lösung

laplace transformation

- 4 sin (4 t)

- \frac{16}{s ^{2} + 16}

Schritte zur Lösung

L {- 4 sin (4 t)}

Verwende die konstante Multiplikationseigenschaft der Laplace-Transformation:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 4 L {sin (4 t)}

L {sin (4 t)} : \frac{4}{s ^{2} + 16}

= - 4 \cdot \frac{4}{s ^{2} + 16}

Fasse

- 4 \frac{4}{s ^{2} + 16}

zusammen:

- \frac{16}{s ^{2} + 16}

= - \frac{16}{s ^{2} + 16}

in v erse l a pl a ce \frac{6}{( s - 2 ) ^{2} ( s - 4 ) ^{4}}

x \frac{d y}{d x} + 1 = x + y

\frac{\partial}{\partial y} (6 - 3 x - 2 y)

\int_{- \infty}^{- 1} e^{- 34 t} d t

n = 1 \sum \infty \frac{2 n}{1 + n ^{4}}