derivative of (x^4/8+1/(4x^2))

Lösung

\frac{d}{d x} (\frac{x ^{4}}{8} + \frac{1}{4 x ^{2}})

\frac{x ^{3}}{2} - \frac{1}{2 x ^{3}}

Schritte zur Lösung

\frac{d}{d x} (\frac{x ^{4}}{8} + \frac{1}{4 x ^{2}})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{4}}{8}) + \frac{d}{d x} (\frac{1}{4 x ^{2}})

\frac{d}{d x} (\frac{x ^{4}}{8}) = \frac{x ^{3}}{2}

\frac{d}{d x} (\frac{1}{4 x ^{2}}) = - \frac{1}{2 x ^{3}}

= \frac{x ^{3}}{2} - \frac{1}{2 x ^{3}}

\int \frac{3 x}{( x + 1 ) ( x - 2 )} d x

n \to \infty lim (\frac{1}{5})

y^{^{'}} = \frac{2 y + x}{x}

n = 0 \sum \infty ln (2)

\int \frac{3 x}{x ^{2}} d x