y^{''}+y^'=1

Lösung

y^{^{''}} + y^{^{'}} = 1

y = c_{1} + c_{2} e^{- t} + t

Schritte zur Lösung

y^{''} (t) + y^{'} (t) = 1

Solve linear ODE:

y = c_{1} + c_{2} e^{- t} + t

y = c_{1} + c_{2} e^{- t} + t

\int_{0}^{1} \frac{e ^{\frac{1}{x}}}{x ^{3}} d x

s l o p e (0, 2.5), (0.833, 0)

t an g e n t f (x) = 2 x^{3} - 2 x, at x = - 1

\frac{\partial}{\partial y} (sin (x + 2 y))

\int_{0}^{π} 2 π x sin (x) d x