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(1+x^2+y^2+x^2y^2)dy=(1+y^2)dx

解答

(1 + x^{2} + y^{2} + x^{2} y^{2}) d y = (1 + y^{2}) d x

解答

y = arctan (x) + c_{1}

求解步骤

(1 + x^{2} + y^{2} + x^{2} y^{2}) d y = (1 + y^{2}) d x

令

y

为因变量。除以

d x

:

(1 + x^{2} + y^{2} + x^{2} y^{2}) \frac{d y}{d x} = 1 + y^{2}

用

y^{'} (x)

替代

\frac{d y}{d x}

(1 + x^{2} + y^{2} + x^{2} y^{2}) y^{^{'}} (x) = 1 + y^{2}

整理

y^{'} (x) : y^{'} (x) = \frac{1}{x ^{2} + 1}

若

f^{^{'}} (x) = g (x)

则

f (x) = \int g (x) d x

y = \int \frac{1}{x ^{2} + 1} d x

\int \frac{1}{x ^{2} + 1} d x = arctan (x) + c_{1}

y = arctan (x) + c_{1}

作图

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