What is the derivative of (x^3+8x)^3 ?

The derivative of (x^3+8x)^3 is 3(x^3+8x)^2(3x^2+8)

What is the first derivative of (x^3+8x)^3 ?

The first derivative of (x^3+8x)^3 is 3(x^3+8x)^2(3x^2+8)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of

(x^{3} + 8 x)^{3}

3 (x^{3} + 8 x)^{2} (3 x^{2} + 8)

Solution steps

\frac{d}{d x} ((x^{3} + 8 x)^{3})

Apply the chain rule:

3 (x^{3} + 8 x)^{2} \frac{d}{d x} (x^{3} + 8 x)

= 3 (x^{3} + 8 x)^{2} \frac{d}{d x} (x^{3} + 8 x)

\frac{d}{d x} (x^{3} + 8 x) = 3 x^{2} + 8

= 3 (x^{3} + 8 x)^{2} (3 x^{2} + 8)

What is the derivative of (x^3+8x)^3 ?
The derivative of (x^3+8x)^3 is 3(x^3+8x)^2(3x^2+8)
What is the first derivative of (x^3+8x)^3 ?
The first derivative of (x^3+8x)^3 is 3(x^3+8x)^2(3x^2+8)