sin(2x)dx+cos(3y)dy=0

Lösung

sin (2 x) d x + cos (3 y) d y = 0

y = \frac{arcsin ( \frac{3}{2} cos ( 2 x ) + c _{1} )}{3} + \frac{2 πn}{3}, y = \frac{π}{3} + \frac{arcsin ( - \frac{3}{2} cos ( 2 x ) - c _{1} )}{3} + \frac{2 πn}{3}

Schritte zur Lösung

sin (2 x) d x + cos (3 y) d y = 0

Solve separable ODE:

y = \frac{arcsin ( \frac{3}{2} cos ( 2 x ) + c _{1} )}{3} + \frac{2 πn}{3}, y = \frac{π}{3} + \frac{arcsin ( - \frac{3}{2} cos ( 2 x ) - c _{1} )}{3} + \frac{2 πn}{3}

y = \frac{arcsin ( \frac{3}{2} cos ( 2 x ) + c _{1} )}{3} + \frac{2 πn}{3}, y = \frac{π}{3} + \frac{arcsin ( - \frac{3}{2} cos ( 2 x ) - c _{1} )}{3} + \frac{2 πn}{3}

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