(\partial)/(\partial x)(2xy+3x-4y+1)

Lösung

\frac{\partial}{\partial x} (2 x y + 3 x - 4 y + 1)

2 y + 3

Schritte zur Lösung

\frac{\partial}{\partial x} (2 x y + 3 x - 4 y + 1)

Behandle

y

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x y) + \frac{\partial}{\partial x} (3 x) - \frac{\partial}{\partial x} (4 y) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (2 x y) = 2 y

\frac{\partial}{\partial x} (3 x) = 3

\frac{\partial}{\partial x} (4 y) = 0

\frac{\partial}{\partial x} (1) = 0

= 2 y + 3 - 0 + 0

Vereinfache

= 2 y + 3

\frac{\partial}{\partial x} (x y^{7} - x^{2} y)

\frac{d}{d x} (\frac{x ^{2}}{4 x + 1})

d er i v a t i v e f (x) = \frac{2 - x ^{2}}{3 + x ^{2}}

n = 1 \sum \infty arctan (18 n)

n = 0 \sum \infty (1.1)^{n}