y^'=x-2y

Lösung

y^{^{'}} = x - 2 y

y = \frac{2 x - 1}{4} + \frac{c _{1}}{e ^{2 x}}

Schritte zur Lösung

y^{'} (x) = x - 2 y

Solve linear ODE:

y = \frac{2 x - 1}{4} + \frac{c _{1}}{e ^{2 x}}

y = \frac{2 x - 1}{4} + \frac{c _{1}}{e ^{2 x}}

s l o p e (1, 4), (- 5, 2)

\int \frac{1}{12 x - 9 x ^{2} - 2} d x

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