(\partial)/(\partial x)(cos(x/(1+y)))

Lösung

\frac{\partial}{\partial x} (cos (\frac{x}{1 + y}))

- \frac{sin ( \frac{x}{1 + y} )}{1 + y}

Schritte zur Lösung

\frac{\partial}{\partial x} (cos (\frac{x}{1 + y}))

Behandle

y

als Konstante

Wende die Kettenregel an:

- sin (\frac{x}{1 + y}) \frac{\partial}{\partial x} (\frac{x}{1 + y})

= - sin (\frac{x}{1 + y}) \frac{\partial}{\partial x} (\frac{x}{1 + y})

\frac{\partial}{\partial x} (\frac{x}{1 + y}) = \frac{1}{1 + y}

= - sin (\frac{x}{1 + y}) \frac{1}{1 + y}

Vereinfache

- sin (\frac{x}{1 + y}) \frac{1}{1 + y} : - \frac{sin ( \frac{x}{1 + y} )}{1 + y}

= - \frac{sin ( \frac{x}{1 + y} )}{1 + y}

x \to 2 + lim (in t x)

\frac{d}{d θ} (sin^{2} (θ))

y^{^{''}} + 49 y = 3 tan (7 x)

t an g e n t f (x) = 2 x + 7, at x = 9

\int \frac{4 x - 11}{x ^{2} - 3 x - 4} d x