y^{''}=-9sin(5x)

Lösung

y^{^{''}} = - 9 sin (5 x)

y = \frac{9}{25} sin (5 x) + c_{1} x + c_{2}

Schritte zur Lösung

y^{''} (x) = - 9 sin (5 x)

Löse

y^{''} (x) = - 9 sin (5 x) : y^{'} (x) = \frac{9}{5} cos (5 x) + c_{1}

Löse

y^{'} (x) = \frac{9}{5} cos (5 x) + c_{1} : y = \frac{9}{25} sin (5 x) + c_{1} x + c_{2}

y = \frac{9}{25} sin (5 x) + c_{1} x + c_{2}

\frac{\partial}{\partial x} (\frac{2}{x} - n)

\int (8 t^{3} - 6 t^{- 2}) d t

x \to - 1^{- 1} lim (\frac{x}{x + 1})

\int \frac{9}{x + 9 + x} d x

d er i v a t i v e f (x) = x^{2} (1 - 8 x)