taylor xcos(2x)

Lösung

taylor

x cos (2 x)

x - 2 x^{3} + \frac{2}{3} x^{5} - \frac{4}{45} x^{7} + \frac{2}{315} x^{9} + \dots

Schritte zur Lösung

Apply the Taylor Formula

= 0 + \frac{\frac{d}{d x} ( x cos ( 2 x ) ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( x cos ( 2 x ) ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( x cos ( 2 x ) ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 0 + \frac{1}{1 !} x + \frac{0}{2 !} x^{2} + \frac{- 12}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{80}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{- 448}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{2304}{9 !} x^{9} + \dots

Fasse zusammen

= x - 2 x^{3} + \frac{2}{3} x^{5} - \frac{4}{45} x^{7} + \frac{2}{315} x^{9} + \dots

\int \frac{( ln ^{2} ( x ^{2} ) )}{x} d x

\int \frac{8 x ^{3}}{0.2 x ^{4} + 8000} d x

\frac{\partial}{\partial y} (x^{y} + y)

x \to 3 lim (\frac{1}{x + 3})

d er i v a t i v e f (x) = 4 x^{10} e^{x}