derivative of x^4-8x^2+a

解答

\frac{d}{d x} (x^{4} - 8 x^{2} + a)

4 x^{3} - 16 x

求解步骤

\frac{d}{d x} (x^{4} - 8 x^{2} + a)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (8 x^{2}) + \frac{d a}{d x}

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (8 x^{2}) = 16 x

\frac{d a}{d x} = 0

= 4 x^{3} - 16 x + 0

化简

= 4 x^{3} - 16 x

\int - x (3 2 x^{2} + 4) d x

\frac{\partial}{\partial x} (e)

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