What is the tangent of (x-y-1)^3=x,(1,-1) ?

The tangent of (x-y-1)^3=x,(1,-1) is y= 2/3 x-5/3

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tangent of (x-y-1)^3=x,(1,-1)

tangent of

(x - y - 1)^{3} = x, (1, - 1)

y = \frac{2}{3} x - \frac{5}{3}

Solution steps

Find the slope of

(x - y - 1)^{3} = x : \frac{d y}{d x} = - \frac{1}{3 x ^{\frac{2}{3}}} + 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{2}{3}

Find the line with slope m=

\frac{2}{3}

and passing through

(1, - 1) : y = \frac{2}{3} x - \frac{5}{3}

y = \frac{2}{3} x - \frac{5}{3}

What is the tangent of (x-y-1)^3=x,(1,-1) ?
The tangent of (x-y-1)^3=x,(1,-1) is y= 2/3 x-5/3