What is the solution for (y-x3)dx+(x+y3)dy=0 ?

The solution for (y-x3)dx+(x+y3)dy=0 is y=(-2x+sqrt(40x^2+c_{1)})/6 ,y=(-2x-sqrt(40x^2+c_{1)})/6

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(y-x3)dx+(x+y3)dy=0

(y - x 3) d x + (x + y 3) d y = 0

y = \frac{- 2 x + 40 x ^{2} + c _{1}}{6}, y = \frac{- 2 x - 40 x ^{2} + c _{1}}{6}

Solution steps

(y - x 3) d x + (x + y 3) d y = 0

Solve exact ODE:

y = \frac{- 2 x + 40 x ^{2} + c _{1}}{6}, y = \frac{- 2 x - 40 x ^{2} + c _{1}}{6}

y = \frac{- 2 x + 40 x ^{2} + c _{1}}{6}, y = \frac{- 2 x - 40 x ^{2} + c _{1}}{6}

What is the solution for (y-x3)dx+(x+y3)dy=0 ?
The solution for (y-x3)dx+(x+y3)dy=0 is y=(-2x+sqrt(40x^2+c_{1)})/6 ,y=(-2x-sqrt(40x^2+c_{1)})/6