What is the tangent of-x^2+7x+2,\at x=3 ?

The tangent of-x^2+7x+2,\at x=3 is y=x+11

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tangent of-x^2+7x+2,\at x=3

tangent of

- x^{2} + 7 x + 2, at x = 3

y = x + 11

Solution steps

Find the tangent point:

(3, 14)

Find the slope of

y = - x^{2} + 7 x + 2 : \frac{d y}{d x} = - 2 x + 7

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1

Find the line with slope m=

1

and passing through

(3, 14) : y = x + 11

y = x + 11

What is the tangent of-x^2+7x+2,\at x=3 ?
The tangent of-x^2+7x+2,\at x=3 is y=x+11