(\partial)/(\partial x)(xy-2x-2y-x^2-y^2)

Lösung

\frac{\partial}{\partial x} (x y - 2 x - 2 y - x^{2} - y^{2})

y - 2 x - 2

Schritte zur Lösung

\frac{\partial}{\partial x} (x y - 2 x - 2 y - x^{2} - y^{2})

Behandle

y

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x y) - \frac{\partial}{\partial x} (2 x) - \frac{\partial}{\partial x} (2 y) - \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (y^{2}) = 0

= y - 2 - 0 - 2 x - 0

Vereinfache

= y - 2 x - 2

\int \frac{x ^{2} - 1}{x ^{3}} d x

\frac{d y}{d t} = 6 e^{2 t - y}

\frac{d}{d x} (m x e^{n x^{2}})

\frac{d}{d x} (5 \cdot T g (T, x) (2 x^{3}) + \frac{2}{x ^{2}})

t an g e n t y = \frac{5}{x}, (1, 5)