derivative sec^2(2x+5)*2

Lösung

ableitung von

sec^{2} (2 x + 5) \cdot 2

8 sec^{2} (2 x + 5) tan (2 x + 5)

Schritte zur Lösung

\frac{d}{d x} (sec^{2} (2 x + 5) \cdot 2)

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sec^{2} (2 x + 5))

Wende die Kettenregel an:

2 sec (2 x + 5) \frac{d}{d x} (sec (2 x + 5))

= 2 sec (2 x + 5) \frac{d}{d x} (sec (2 x + 5))

\frac{d}{d x} (sec (2 x + 5)) = sec (2 x + 5) tan (2 x + 5) \cdot 2

= 2 \cdot 2 sec (2 x + 5) sec (2 x + 5) tan (2 x + 5) \cdot 2

Vereinfache

2 \cdot 2 sec (2 x + 5) sec (2 x + 5) tan (2 x + 5) \cdot 2 : 8 sec^{2} (2 x + 5) tan (2 x + 5)

= 8 sec^{2} (2 x + 5) tan (2 x + 5)

n \to 2 lim (n^{2})

d er i v a t i v e f (x) = (5 x - 5) (2 x^{3} - x^{2} + 1)

\frac{\partial}{\partial u} (u^{5} + v^{9})

\int_{1}^{e^{4}} \frac{ln ^{3} ( x ^{2} )}{x} d x

\frac{d}{d x} (x^{\frac{4}{3}} + 4 x^{\frac{1}{3}})