y^{''}+12y^'+36=0

Lösung

y^{^{''}} + 12 y^{^{'}} + 36 = 0

y = c_{1} + c_{2} e^{- 12 t} - 3 t

Schritte zur Lösung

y^{''} (t) + 12 y^{'} (t) + 36 = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 12 t} - 3 t

y = c_{1} + c_{2} e^{- 12 t} - 3 t

\frac{\partial}{\partial x} (y e^{x} + x ln (z))

t y^{^{'}} = 4 t^{2} - 2 y

y^{^{''}} x = y^{^{'}}

\frac{\partial}{\partial u} (u v^{2} + w^{3})

\frac{\partial}{\partial x} (x^{2} y e^{x y})